\(\int \frac {1}{x^4 \sqrt [3]{1-x^2} (3+x^2)^2} \, dx\) [1030]

Optimal result

Integrand size = 22, antiderivative size = 581 \[ \int \frac {1}{x^4 \sqrt [3]{1-x^2} \left (3+x^2\right )^2} \, dx=-\frac {11 \left (1-x^2\right )^{2/3}}{216 x^3}+\frac {11 \left (1-x^2\right )^{2/3}}{648 x}+\frac {\left (1-x^2\right )^{2/3}}{24 x^3 \left (3+x^2\right )}-\frac {11 x}{648 \left (1-\sqrt {3}-\sqrt [3]{1-x^2}\right )}+\frac {11 \arctan \left (\frac {\sqrt {3}}{x}\right )}{216\ 2^{2/3} \sqrt {3}}+\frac {11 \arctan \left (\frac {\sqrt {3} \left (1-\sqrt [3]{2} \sqrt [3]{1-x^2}\right )}{x}\right )}{216\ 2^{2/3} \sqrt {3}}-\frac {11 \text {arctanh}(x)}{648\ 2^{2/3}}+\frac {11 \text {arctanh}\left (\frac {x}{1+\sqrt [3]{2} \sqrt [3]{1-x^2}}\right )}{216\ 2^{2/3}}-\frac {11 \sqrt {2+\sqrt {3}} \left (1-\sqrt [3]{1-x^2}\right ) \sqrt {\frac {1+\sqrt [3]{1-x^2}+\left (1-x^2\right )^{2/3}}{\left (1-\sqrt {3}-\sqrt [3]{1-x^2}\right )^2}} E\left (\arcsin \left (\frac {1+\sqrt {3}-\sqrt [3]{1-x^2}}{1-\sqrt {3}-\sqrt [3]{1-x^2}}\right )|-7+4 \sqrt {3}\right )}{432\ 3^{3/4} x \sqrt {-\frac {1-\sqrt [3]{1-x^2}}{\left (1-\sqrt {3}-\sqrt [3]{1-x^2}\right )^2}}}+\frac {11 \left (1-\sqrt [3]{1-x^2}\right ) \sqrt {\frac {1+\sqrt [3]{1-x^2}+\left (1-x^2\right )^{2/3}}{\left (1-\sqrt {3}-\sqrt [3]{1-x^2}\right )^2}} \operatorname {EllipticF}\left (\arcsin \left (\frac {1+\sqrt {3}-\sqrt [3]{1-x^2}}{1-\sqrt {3}-\sqrt [3]{1-x^2}}\right ),-7+4 \sqrt {3}\right )}{324 \sqrt {2} \sqrt [4]{3} x \sqrt {-\frac {1-\sqrt [3]{1-x^2}}{\left (1-\sqrt {3}-\sqrt [3]{1-x^2}\right )^2}}} \]

[Out]

-11/216*(-x^2+1)^(2/3)/x^3+11/648*(-x^2+1)^(2/3)/x+1/24*(-x^2+1)^(2/3)/x^3/(x^2+3)-11/1296*arctanh(x)*2^(1/3)+
11/432*arctanh(x/(1+2^(1/3)*(-x^2+1)^(1/3)))*2^(1/3)-11/648*x/(1-(-x^2+1)^(1/3)-3^(1/2))+11/1296*arctan(3^(1/2
)/x)*2^(1/3)*3^(1/2)+11/1296*arctan((1-2^(1/3)*(-x^2+1)^(1/3))*3^(1/2)/x)*2^(1/3)*3^(1/2)+11/1944*3^(3/4)*(1-(
-x^2+1)^(1/3))*EllipticF((1-(-x^2+1)^(1/3)+3^(1/2))/(1-(-x^2+1)^(1/3)-3^(1/2)),2*I-I*3^(1/2))*2^(1/2)*((1+(-x^
2+1)^(1/3)+(-x^2+1)^(2/3))/(1-(-x^2+1)^(1/3)-3^(1/2))^2)^(1/2)/x/((-1+(-x^2+1)^(1/3))/(1-(-x^2+1)^(1/3)-3^(1/2
))^2)^(1/2)-11/1296*3^(1/4)*(1-(-x^2+1)^(1/3))*EllipticE((1-(-x^2+1)^(1/3)+3^(1/2))/(1-(-x^2+1)^(1/3)-3^(1/2))
,2*I-I*3^(1/2))*((1+(-x^2+1)^(1/3)+(-x^2+1)^(2/3))/(1-(-x^2+1)^(1/3)-3^(1/2))^2)^(1/2)*(1/2*6^(1/2)+1/2*2^(1/2
))/x/((-1+(-x^2+1)^(1/3))/(1-(-x^2+1)^(1/3)-3^(1/2))^2)^(1/2)

Rubi [A] (verified)

Time = 0.26 (sec) , antiderivative size = 581, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.364, Rules used = {483, 597, 544, 241, 310, 225, 1893, 402} \[ \int \frac {1}{x^4 \sqrt [3]{1-x^2} \left (3+x^2\right )^2} \, dx=\frac {11 \left (1-\sqrt [3]{1-x^2}\right ) \sqrt {\frac {\left (1-x^2\right )^{2/3}+\sqrt [3]{1-x^2}+1}{\left (-\sqrt [3]{1-x^2}-\sqrt {3}+1\right )^2}} \operatorname {EllipticF}\left (\arcsin \left (\frac {-\sqrt [3]{1-x^2}+\sqrt {3}+1}{-\sqrt [3]{1-x^2}-\sqrt {3}+1}\right ),-7+4 \sqrt {3}\right )}{324 \sqrt {2} \sqrt [4]{3} \sqrt {-\frac {1-\sqrt [3]{1-x^2}}{\left (-\sqrt [3]{1-x^2}-\sqrt {3}+1\right )^2}} x}-\frac {11 \sqrt {2+\sqrt {3}} \left (1-\sqrt [3]{1-x^2}\right ) \sqrt {\frac {\left (1-x^2\right )^{2/3}+\sqrt [3]{1-x^2}+1}{\left (-\sqrt [3]{1-x^2}-\sqrt {3}+1\right )^2}} E\left (\arcsin \left (\frac {-\sqrt [3]{1-x^2}+\sqrt {3}+1}{-\sqrt [3]{1-x^2}-\sqrt {3}+1}\right )|-7+4 \sqrt {3}\right )}{432\ 3^{3/4} \sqrt {-\frac {1-\sqrt [3]{1-x^2}}{\left (-\sqrt [3]{1-x^2}-\sqrt {3}+1\right )^2}} x}+\frac {11 \arctan \left (\frac {\sqrt {3} \left (1-\sqrt [3]{2} \sqrt [3]{1-x^2}\right )}{x}\right )}{216\ 2^{2/3} \sqrt {3}}+\frac {11 \arctan \left (\frac {\sqrt {3}}{x}\right )}{216\ 2^{2/3} \sqrt {3}}+\frac {11 \text {arctanh}\left (\frac {x}{\sqrt [3]{2} \sqrt [3]{1-x^2}+1}\right )}{216\ 2^{2/3}}-\frac {11 \text {arctanh}(x)}{648\ 2^{2/3}}-\frac {11 x}{648 \left (-\sqrt [3]{1-x^2}-\sqrt {3}+1\right )}+\frac {11 \left (1-x^2\right )^{2/3}}{648 x}-\frac {11 \left (1-x^2\right )^{2/3}}{216 x^3}+\frac {\left (1-x^2\right )^{2/3}}{24 \left (x^2+3\right ) x^3} \]

[In]

Int[1/(x^4*(1 - x^2)^(1/3)*(3 + x^2)^2),x]

[Out]

(-11*(1 - x^2)^(2/3))/(216*x^3) + (11*(1 - x^2)^(2/3))/(648*x) + (1 - x^2)^(2/3)/(24*x^3*(3 + x^2)) - (11*x)/(
648*(1 - Sqrt[3] - (1 - x^2)^(1/3))) + (11*ArcTan[Sqrt[3]/x])/(216*2^(2/3)*Sqrt[3]) + (11*ArcTan[(Sqrt[3]*(1 -
2^(1/3)*(1 - x^2)^(1/3)))/x])/(216*2^(2/3)*Sqrt[3]) - (11*ArcTanh[x])/(648*2^(2/3)) + (11*ArcTanh[x/(1 + 2^(1
/3)*(1 - x^2)^(1/3))])/(216*2^(2/3)) - (11*Sqrt[2 + Sqrt[3]]*(1 - (1 - x^2)^(1/3))*Sqrt[(1 + (1 - x^2)^(1/3) +
(1 - x^2)^(2/3))/(1 - Sqrt[3] - (1 - x^2)^(1/3))^2]*EllipticE[ArcSin[(1 + Sqrt[3] - (1 - x^2)^(1/3))/(1 - Sqr
t[3] - (1 - x^2)^(1/3))], -7 + 4*Sqrt[3]])/(432*3^(3/4)*x*Sqrt[-((1 - (1 - x^2)^(1/3))/(1 - Sqrt[3] - (1 - x^2
)^(1/3))^2)]) + (11*(1 - (1 - x^2)^(1/3))*Sqrt[(1 + (1 - x^2)^(1/3) + (1 - x^2)^(2/3))/(1 - Sqrt[3] - (1 - x^2
)^(1/3))^2]*EllipticF[ArcSin[(1 + Sqrt[3] - (1 - x^2)^(1/3))/(1 - Sqrt[3] - (1 - x^2)^(1/3))], -7 + 4*Sqrt[3]]
)/(324*Sqrt[2]*3^(1/4)*x*Sqrt[-((1 - (1 - x^2)^(1/3))/(1 - Sqrt[3] - (1 - x^2)^(1/3))^2)])

Rule 225

Int[1/Sqrt[(a_) + (b_.)*(x_)^3], x_Symbol] :> With[{r = Numer[Rt[b/a, 3]], s = Denom[Rt[b/a, 3]]}, Simp[2*Sqrt
[2 - Sqrt[3]]*(s + r*x)*(Sqrt[(s^2 - r*s*x + r^2*x^2)/((1 - Sqrt[3])*s + r*x)^2]/(3^(1/4)*r*Sqrt[a + b*x^3]*Sq
rt[(-s)*((s + r*x)/((1 - Sqrt[3])*s + r*x)^2)]))*EllipticF[ArcSin[((1 + Sqrt[3])*s + r*x)/((1 - Sqrt[3])*s + r
*x)], -7 + 4*Sqrt[3]], x]] /; FreeQ[{a, b}, x] && NegQ[a]

Rule 241

Int[((a_) + (b_.)*(x_)^2)^(-1/3), x_Symbol] :> Dist[3*(Sqrt[b*x^2]/(2*b*x)), Subst[Int[x/Sqrt[-a + x^3], x], x
, (a + b*x^2)^(1/3)], x] /; FreeQ[{a, b}, x]

Rule 310

Int[(x_)/Sqrt[(a_) + (b_.)*(x_)^3], x_Symbol] :> With[{r = Numer[Rt[b/a, 3]], s = Denom[Rt[b/a, 3]]}, Dist[(-(
1 + Sqrt[3]))*(s/r), Int[1/Sqrt[a + b*x^3], x], x] + Dist[1/r, Int[((1 + Sqrt[3])*s + r*x)/Sqrt[a + b*x^3], x]
, x]] /; FreeQ[{a, b}, x] && NegQ[a]

Rule 402

Int[1/(((a_) + (b_.)*(x_)^2)^(1/3)*((c_) + (d_.)*(x_)^2)), x_Symbol] :> With[{q = Rt[-b/a, 2]}, Simp[q*(ArcTan
[Sqrt[3]/(q*x)]/(2*2^(2/3)*Sqrt[3]*a^(1/3)*d)), x] + (Simp[q*(ArcTanh[(a^(1/3)*q*x)/(a^(1/3) + 2^(1/3)*(a + b*
x^2)^(1/3))]/(2*2^(2/3)*a^(1/3)*d)), x] - Simp[q*(ArcTanh[q*x]/(6*2^(2/3)*a^(1/3)*d)), x] + Simp[q*(ArcTan[Sqr
t[3]*((a^(1/3) - 2^(1/3)*(a + b*x^2)^(1/3))/(a^(1/3)*q*x))]/(2*2^(2/3)*Sqrt[3]*a^(1/3)*d)), x])] /; FreeQ[{a,
b, c, d}, x] && NeQ[b*c - a*d, 0] && EqQ[b*c + 3*a*d, 0] && NegQ[b/a]

Rule 483

Int[((e_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_)*((c_) + (d_.)*(x_)^(n_))^(q_), x_Symbol] :> Simp[(-b)*(e*
x)^(m + 1)*(a + b*x^n)^(p + 1)*((c + d*x^n)^(q + 1)/(a*e*n*(b*c - a*d)*(p + 1))), x] + Dist[1/(a*n*(b*c - a*d)
*(p + 1)), Int[(e*x)^m*(a + b*x^n)^(p + 1)*(c + d*x^n)^q*Simp[c*b*(m + 1) + n*(b*c - a*d)*(p + 1) + d*b*(m + n
*(p + q + 2) + 1)*x^n, x], x], x] /; FreeQ[{a, b, c, d, e, m, q}, x] && NeQ[b*c - a*d, 0] && IGtQ[n, 0] && LtQ
[p, -1] && IntBinomialQ[a, b, c, d, e, m, n, p, q, x]

Rule 544

Int[(((a_) + (b_.)*(x_)^(n_))^(p_)*((e_) + (f_.)*(x_)^(n_)))/((c_) + (d_.)*(x_)^(n_)), x_Symbol] :> Dist[f/d,
Int[(a + b*x^n)^p, x], x] + Dist[(d*e - c*f)/d, Int[(a + b*x^n)^p/(c + d*x^n), x], x] /; FreeQ[{a, b, c, d, e,
f, p, n}, x]

Rule 597

Int[((g_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^(n_))^(p_.)*((c_) + (d_.)*(x_)^(n_))^(q_.)*((e_) + (f_.)*(x_)^(n_)),
x_Symbol] :> Simp[e*(g*x)^(m + 1)*(a + b*x^n)^(p + 1)*((c + d*x^n)^(q + 1)/(a*c*g*(m + 1))), x] + Dist[1/(a*c*
g^n*(m + 1)), Int[(g*x)^(m + n)*(a + b*x^n)^p*(c + d*x^n)^q*Simp[a*f*c*(m + 1) - e*(b*c + a*d)*(m + n + 1) - e
*n*(b*c*p + a*d*q) - b*e*d*(m + n*(p + q + 2) + 1)*x^n, x], x], x] /; FreeQ[{a, b, c, d, e, f, g, p, q}, x] &&
IGtQ[n, 0] && LtQ[m, -1]

Rule 1893

Int[((c_) + (d_.)*(x_))/Sqrt[(a_) + (b_.)*(x_)^3], x_Symbol] :> With[{r = Numer[Simplify[(1 + Sqrt[3])*(d/c)]]
, s = Denom[Simplify[(1 + Sqrt[3])*(d/c)]]}, Simp[2*d*s^3*(Sqrt[a + b*x^3]/(a*r^2*((1 - Sqrt[3])*s + r*x))), x
] + Simp[3^(1/4)*Sqrt[2 + Sqrt[3]]*d*s*(s + r*x)*(Sqrt[(s^2 - r*s*x + r^2*x^2)/((1 - Sqrt[3])*s + r*x)^2]/(r^2
*Sqrt[a + b*x^3]*Sqrt[(-s)*((s + r*x)/((1 - Sqrt[3])*s + r*x)^2)]))*EllipticE[ArcSin[((1 + Sqrt[3])*s + r*x)/(
(1 - Sqrt[3])*s + r*x)], -7 + 4*Sqrt[3]], x]] /; FreeQ[{a, b, c, d}, x] && NegQ[a] && EqQ[b*c^3 - 2*(5 + 3*Sqr
t[3])*a*d^3, 0]

Rubi steps \begin{align*} \text {integral}& = \frac {\left (1-x^2\right )^{2/3}}{24 x^3 \left (3+x^2\right )}-\frac {1}{24} \int \frac {-11+\frac {11 x^2}{3}}{x^4 \sqrt [3]{1-x^2} \left (3+x^2\right )} \, dx \\ & = -\frac {11 \left (1-x^2\right )^{2/3}}{216 x^3}+\frac {\left (1-x^2\right )^{2/3}}{24 x^3 \left (3+x^2\right )}+\frac {1}{216} \int \frac {-11+\frac {55 x^2}{3}}{x^2 \sqrt [3]{1-x^2} \left (3+x^2\right )} \, dx \\ & = -\frac {11 \left (1-x^2\right )^{2/3}}{216 x^3}+\frac {11 \left (1-x^2\right )^{2/3}}{648 x}+\frac {\left (1-x^2\right )^{2/3}}{24 x^3 \left (3+x^2\right )}-\frac {1}{648} \int \frac {-77-\frac {11 x^2}{3}}{\sqrt [3]{1-x^2} \left (3+x^2\right )} \, dx \\ & = -\frac {11 \left (1-x^2\right )^{2/3}}{216 x^3}+\frac {11 \left (1-x^2\right )^{2/3}}{648 x}+\frac {\left (1-x^2\right )^{2/3}}{24 x^3 \left (3+x^2\right )}+\frac {11 \int \frac {1}{\sqrt [3]{1-x^2}} \, dx}{1944}+\frac {11}{108} \int \frac {1}{\sqrt [3]{1-x^2} \left (3+x^2\right )} \, dx \\ & = -\frac {11 \left (1-x^2\right )^{2/3}}{216 x^3}+\frac {11 \left (1-x^2\right )^{2/3}}{648 x}+\frac {\left (1-x^2\right )^{2/3}}{24 x^3 \left (3+x^2\right )}+\frac {11 \tan ^{-1}\left (\frac {\sqrt {3}}{x}\right )}{216\ 2^{2/3} \sqrt {3}}+\frac {11 \tan ^{-1}\left (\frac {\sqrt {3} \left (1-\sqrt [3]{2} \sqrt [3]{1-x^2}\right )}{x}\right )}{216\ 2^{2/3} \sqrt {3}}-\frac {11 \tanh ^{-1}(x)}{648\ 2^{2/3}}+\frac {11 \tanh ^{-1}\left (\frac {x}{1+\sqrt [3]{2} \sqrt [3]{1-x^2}}\right )}{216\ 2^{2/3}}-\frac {\left (11 \sqrt {-x^2}\right ) \text {Subst}\left (\int \frac {x}{\sqrt {-1+x^3}} \, dx,x,\sqrt [3]{1-x^2}\right )}{1296 x} \\ & = -\frac {11 \left (1-x^2\right )^{2/3}}{216 x^3}+\frac {11 \left (1-x^2\right )^{2/3}}{648 x}+\frac {\left (1-x^2\right )^{2/3}}{24 x^3 \left (3+x^2\right )}+\frac {11 \tan ^{-1}\left (\frac {\sqrt {3}}{x}\right )}{216\ 2^{2/3} \sqrt {3}}+\frac {11 \tan ^{-1}\left (\frac {\sqrt {3} \left (1-\sqrt [3]{2} \sqrt [3]{1-x^2}\right )}{x}\right )}{216\ 2^{2/3} \sqrt {3}}-\frac {11 \tanh ^{-1}(x)}{648\ 2^{2/3}}+\frac {11 \tanh ^{-1}\left (\frac {x}{1+\sqrt [3]{2} \sqrt [3]{1-x^2}}\right )}{216\ 2^{2/3}}+\frac {\left (11 \sqrt {-x^2}\right ) \text {Subst}\left (\int \frac {1+\sqrt {3}-x}{\sqrt {-1+x^3}} \, dx,x,\sqrt [3]{1-x^2}\right )}{1296 x}-\frac {\left (11 \left (1+\sqrt {3}\right ) \sqrt {-x^2}\right ) \text {Subst}\left (\int \frac {1}{\sqrt {-1+x^3}} \, dx,x,\sqrt [3]{1-x^2}\right )}{1296 x} \\ & = -\frac {11 \left (1-x^2\right )^{2/3}}{216 x^3}+\frac {11 \left (1-x^2\right )^{2/3}}{648 x}+\frac {\left (1-x^2\right )^{2/3}}{24 x^3 \left (3+x^2\right )}-\frac {11 x}{648 \left (1-\sqrt {3}-\sqrt [3]{1-x^2}\right )}+\frac {11 \tan ^{-1}\left (\frac {\sqrt {3}}{x}\right )}{216\ 2^{2/3} \sqrt {3}}+\frac {11 \tan ^{-1}\left (\frac {\sqrt {3} \left (1-\sqrt [3]{2} \sqrt [3]{1-x^2}\right )}{x}\right )}{216\ 2^{2/3} \sqrt {3}}-\frac {11 \tanh ^{-1}(x)}{648\ 2^{2/3}}+\frac {11 \tanh ^{-1}\left (\frac {x}{1+\sqrt [3]{2} \sqrt [3]{1-x^2}}\right )}{216\ 2^{2/3}}-\frac {11 \sqrt {2+\sqrt {3}} \left (1-\sqrt [3]{1-x^2}\right ) \sqrt {\frac {1+\sqrt [3]{1-x^2}+\left (1-x^2\right )^{2/3}}{\left (1-\sqrt {3}-\sqrt [3]{1-x^2}\right )^2}} E\left (\sin ^{-1}\left (\frac {1+\sqrt {3}-\sqrt [3]{1-x^2}}{1-\sqrt {3}-\sqrt [3]{1-x^2}}\right )|-7+4 \sqrt {3}\right )}{432\ 3^{3/4} x \sqrt {-\frac {1-\sqrt [3]{1-x^2}}{\left (1-\sqrt {3}-\sqrt [3]{1-x^2}\right )^2}}}+\frac {11 \left (1-\sqrt [3]{1-x^2}\right ) \sqrt {\frac {1+\sqrt [3]{1-x^2}+\left (1-x^2\right )^{2/3}}{\left (1-\sqrt {3}-\sqrt [3]{1-x^2}\right )^2}} F\left (\sin ^{-1}\left (\frac {1+\sqrt {3}-\sqrt [3]{1-x^2}}{1-\sqrt {3}-\sqrt [3]{1-x^2}}\right )|-7+4 \sqrt {3}\right )}{324 \sqrt {2} \sqrt [4]{3} x \sqrt {-\frac {1-\sqrt [3]{1-x^2}}{\left (1-\sqrt {3}-\sqrt [3]{1-x^2}\right )^2}}} \\ \end{align*}

Mathematica [C] (warning: unable to verify)

Result contains higher order function than in optimal. Order 6 vs. order 4 in optimal.

Time = 10.11 (sec) , antiderivative size = 173, normalized size of antiderivative = 0.30 \[ \int \frac {1}{x^4 \sqrt [3]{1-x^2} \left (3+x^2\right )^2} \, dx=\frac {11 x^6 \operatorname {AppellF1}\left (\frac {3}{2},\frac {1}{3},1,\frac {5}{2},x^2,-\frac {x^2}{3}\right )+\frac {27 \left (-72+72 x^2+11 x^4-11 x^6+\frac {693 x^4 \operatorname {AppellF1}\left (\frac {1}{2},\frac {1}{3},1,\frac {3}{2},x^2,-\frac {x^2}{3}\right )}{9 \operatorname {AppellF1}\left (\frac {1}{2},\frac {1}{3},1,\frac {3}{2},x^2,-\frac {x^2}{3}\right )+2 x^2 \left (-\operatorname {AppellF1}\left (\frac {3}{2},\frac {1}{3},2,\frac {5}{2},x^2,-\frac {x^2}{3}\right )+\operatorname {AppellF1}\left (\frac {3}{2},\frac {4}{3},1,\frac {5}{2},x^2,-\frac {x^2}{3}\right )\right )}\right )}{\sqrt [3]{1-x^2} \left (3+x^2\right )}}{17496 x^3} \]

[In]

Integrate[1/(x^4*(1 - x^2)^(1/3)*(3 + x^2)^2),x]

[Out]

(11*x^6*AppellF1[3/2, 1/3, 1, 5/2, x^2, -1/3*x^2] + (27*(-72 + 72*x^2 + 11*x^4 - 11*x^6 + (693*x^4*AppellF1[1/
2, 1/3, 1, 3/2, x^2, -1/3*x^2])/(9*AppellF1[1/2, 1/3, 1, 3/2, x^2, -1/3*x^2] + 2*x^2*(-AppellF1[3/2, 1/3, 2, 5
/2, x^2, -1/3*x^2] + AppellF1[3/2, 4/3, 1, 5/2, x^2, -1/3*x^2]))))/((1 - x^2)^(1/3)*(3 + x^2)))/(17496*x^3)

Maple [F]

\[\int \frac {1}{x^{4} \left (-x^{2}+1\right )^{\frac {1}{3}} \left (x^{2}+3\right )^{2}}d x\]

[In]

int(1/x^4/(-x^2+1)^(1/3)/(x^2+3)^2,x)

[Out]

int(1/x^4/(-x^2+1)^(1/3)/(x^2+3)^2,x)

Fricas [F]

\[ \int \frac {1}{x^4 \sqrt [3]{1-x^2} \left (3+x^2\right )^2} \, dx=\int { \frac {1}{{\left (x^{2} + 3\right )}^{2} {\left (-x^{2} + 1\right )}^{\frac {1}{3}} x^{4}} \,d x } \]

[In]

integrate(1/x^4/(-x^2+1)^(1/3)/(x^2+3)^2,x, algorithm="fricas")

[Out]

integral(-(-x^2 + 1)^(2/3)/(x^10 + 5*x^8 + 3*x^6 - 9*x^4), x)

Sympy [F]

\[ \int \frac {1}{x^4 \sqrt [3]{1-x^2} \left (3+x^2\right )^2} \, dx=\int \frac {1}{x^{4} \sqrt [3]{- \left (x - 1\right ) \left (x + 1\right )} \left (x^{2} + 3\right )^{2}}\, dx \]

[In]

integrate(1/x**4/(-x**2+1)**(1/3)/(x**2+3)**2,x)

[Out]

Integral(1/(x**4*(-(x - 1)*(x + 1))**(1/3)*(x**2 + 3)**2), x)

Maxima [F]

\[ \int \frac {1}{x^4 \sqrt [3]{1-x^2} \left (3+x^2\right )^2} \, dx=\int { \frac {1}{{\left (x^{2} + 3\right )}^{2} {\left (-x^{2} + 1\right )}^{\frac {1}{3}} x^{4}} \,d x } \]

[In]

integrate(1/x^4/(-x^2+1)^(1/3)/(x^2+3)^2,x, algorithm="maxima")

[Out]

integrate(1/((x^2 + 3)^2*(-x^2 + 1)^(1/3)*x^4), x)

Giac [F]

\[ \int \frac {1}{x^4 \sqrt [3]{1-x^2} \left (3+x^2\right )^2} \, dx=\int { \frac {1}{{\left (x^{2} + 3\right )}^{2} {\left (-x^{2} + 1\right )}^{\frac {1}{3}} x^{4}} \,d x } \]

[In]

integrate(1/x^4/(-x^2+1)^(1/3)/(x^2+3)^2,x, algorithm="giac")

[Out]

integrate(1/((x^2 + 3)^2*(-x^2 + 1)^(1/3)*x^4), x)

Mupad [F(-1)]

Timed out. \[ \int \frac {1}{x^4 \sqrt [3]{1-x^2} \left (3+x^2\right )^2} \, dx=\int \frac {1}{x^4\,{\left (1-x^2\right )}^{1/3}\,{\left (x^2+3\right )}^2} \,d x \]

[In]

int(1/(x^4*(1 - x^2)^(1/3)*(x^2 + 3)^2),x)

[Out]

int(1/(x^4*(1 - x^2)^(1/3)*(x^2 + 3)^2), x)